FUCK THE POLICE
911 EVERY DAY
INCORRECT!
How about 42?
INCORRECT!
How about 42?
Yes, but fractions are not numerical values, only numeric representations or division formulas. 1/3 tells you nothing of value, unless you know what it is in relation to. 1/3 of WHAT? So you continue to toss out a numerical representation or formula, in which the 'remainder' has already been assumed, as proof that you do not need to assume the remainder!
LOL... AGAIN... for the 5,000,000,000th time... I have NEVER EVER EVER said that "equal thirds do not exist!" How many fucking times do I have to correct that lie? It has never been my argument, I have never stated such an argument, and if this is what you believe I have stated, it explains a lot about why you don't understand what I have said at all.
That's true of all numbers, knuckledragger. 1 tells you nothing unless you know 1 of what. 3 tells you nothing unless you know 3 of what.
1/3 IS a numerical value.
Fractions are NOT values, and I can prove this... here is a little 'fractional' problem...
You have 1 U.S. Gallon of Water... we all know what a gallon is, and 1 is a numerical value. Understood? Ok, each day, you may consume 1/2 of the water. How many days will the water last? Go ahead, calculate the answer for me!
Nope.... 1/3 is a numerical representation, you posted the definition yourself.
You are changing the existent that the fraction measures. The first day it is 1/2 of a gallon, the next day it is 1/2 of 1/2 of a gallon, etc.. In other words, you are moving the target. That is not proof that a fraction is not a numerical value. It is proof that you are an idiot.
Numerical value means a value expressed/represented with numbers rather than letters. That's all it means. And it is synonymous to numerical representation.
Nope.... 1/3 is a numerical representation, you posted the definition yourself.
LOL... "that a fraction measures?" How can a definitive value "measure?" It is a calculation, a divisional calculation, and it's value is dependent on what is being measured, the fraction itself, has no inherent numerical value whatsoever, until you assign it to something to measure. You are the idiot, not me.
And why are you avoiding my point that 1 means nothing unless you know 1 of what. What is the market price for 1? How much does 1 weigh? How many 1s can fit in a phone booth? You claim this attribute makes 1/3 not a numerical value, so does it make 1 not a numerical value?
ALL NUMBERS ARE MEASUREMENTS! NUMBERS HAVE NO INHERENT "VALUE" UNTIL YOU ASSIGN THEM TO SOMETHING TO MEASURE.
Numbers are just symbols representing a sum of units. I was telling you this when the thread started on fp.
Something can't be a value and also be a calculation of value, it's impossible.
1 means 1, no matter what you apply it to. It has the same value always. 1/2 changes in value, depending on how it's applied, because it is a numerical representation.
I gave you an example problem and you accused me of changing the parameters, but I didn't change anything.
If 1/2 has a defined value, you should be able to tell me an answer to the problem.
If you had a gallon of water and were allowed to consume 1 oz. per day, it would last 128 days exactly.
Representing a SUM of UNITS! Correct... but a fraction doesn't do this, it doesn't represent any static sum, it is dependent on the application to define or measure value. The other example I gave is just as illustrative, if I tell you I have 5 liters of gas in my car, you can calculate how many gallons I have... If I tell you I have 1/2 of a tank, you can't, until you know how much a full tank is.
Well if you don't need to assume the remainder, what happened to it? It clearly exists in your equation, so it has to be rectified or you have to assume it. There is no other option but to assume it, we can't calculate infinity. One divided by three equals .3 with a remainder of .1, and you can keep continuing to divide that remainder forever, you will not resolve it. If it can't ever be resolved, it has to be assumed, there is no other alternative. Eventually, one of the three parts of the thirds will have to include this extra portion, or remainder, there is no other way to resolve the problem. And YES, it can be resolved in different base math, and YES it can be assumed or perceived as resolved in base 10 math, that is not my argument. Never has been.