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The Almighty
My guess is he will continue to tell us how close we keep getting without revealing how 'brilliant' he is.
My second guess is we are about to see some of that famous "1/3 logic"
Quick Logic Problem
- Thread starter KingCondanomation
- Start date
My guess is he will continue to tell us how close we keep getting without revealing how 'brilliant' he is.
My second guess is we are about to see some of that famous "1/3 logic"
Thorn
Member
Battleborne
Terminator
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The Almighty
Actually it does matter. It is the same as the dice scenario. For 11 you have a 5-6 combo and a 6-5 combo.
Dano just told me their are more than four possibilities.
KingCondanomation
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The Almighty
Guess what?
that was my first guess and he said that was wrong too. Then you stated the dice scenario and I realized my mistake. You were correct at 25%
KingCondanomation
New member
More than 4 possibilities for the 2 women combined, yes.
KingCondanomation
New member
Nope
KingCondanomation
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The Almighty
1) you said the women were not related.
2) you said they each had one boy.
3) the odds of them having two boys do not change based on the order you list the kids.
KingCondanomation
New member
Number 3 is false.
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The Almighty
Then please oh wise Dano... tell us how that changes the odds
Thorn
Member
Sure about that are you?
No, I'm confusing myself. I revert back to my original answer. We already know the gender of the first child. Unless I've read the original question incorrectly and more children are involved, which wouldn't affect the answer unless you're limiting it to only 2 boys and not "at least" 2 boys each. If twins are involved ... Never mind, I'm going to reread the original question.
KingCondanomation
New member
Easy man, this is just a bit of fun.
To answer your question, you need to reread the original problem very closely.
Another (bigger) hint: It is certainly true that Joan has a 1 in 2 shot of having 2 boys.
Epicurus
Reasonable
See I did that a bunch of times and the only play on the wording is that he specifies the relative age of one of the children. The question is worded in a way that leaves little room for deception.
So I'm really curious to see the answer to this, since it apparently defies mathematics and genetics.
Thorn
Member
Does it have something to do with the tense "oldest" child vs. "older" child; the problem states that each has two children, not that each has at least two children.
At least one of Joan's children is a boy. In standard logic problems that language tells us not to make any assumptions about the second child. On the other hand, "oldest" implies at least three, but only two were acknowledged.
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The Almighty
What he is trying to say is that you have more options....
Because Joans kids are fixed... the oldest is a boy. Janes are not fixed. She could have girl boy or boy girl.
Thus the possibilities
boy girl boy boy
boy girl boy girl
boy boy boy boy
boy boy boy girl
girl boy boy boy
girl boy boy girl
16.6666666666666666666666666666666666666666666666666666%
But wait, that does not exist, because of rounding. You can't have a number like that. Whatever shall we do.
Because Joans kids are fixed... the oldest is a boy. Janes are not fixed. She could have girl boy or boy girl.
Thus the possibilities
boy girl boy boy
boy girl boy girl
boy boy boy boy
boy boy boy girl
girl boy boy boy
girl boy boy girl
16.6666666666666666666666666666666666666666666666666666%
But wait, that does not exist, because of rounding. You can't have a number like that. Whatever shall we do.
KingCondanomation
New member
They each have 2 children. Joan's children are not related to Jane's children.
KingCondanomation
New member
DING DING. The winner!
Thorn
Member
The birth order doesn't matter. The other child is either a girl or a boy in each of the two families.